Line slope calculator 4x+y=5
Straight line given by points A[0; 5] and B[1; 1]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+5
Canonical form of the line equation: 4x+y-5 = 0
Parametric form of the line equation:
x = t
y = -4t+5 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 1.25
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 1.2127
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [0.5; 3]
Perpendicular Bisector equation: x-4y+11.5 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (1; 1) ; |OB| = 1.4142
Scalar product OA .OB = 5
Angle ∠ AOB = 45° = 0.7854 rad