Line slope calculator 3x+y=5
Straight line given by points A[0; 5] and B[1; 2]
Calculation:
Slope: m = -3Slope-intercept form of line: y = -3x+5
Canonical form of the line equation: 3x+y-5 = 0
Parametric form of the line equation:
x = t
y = -3t+5 ; t ∈ R
Slope angle of line: φ = -71°33'54″ = -1.249 rad
X intercept: x0 = 1.6667
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 1.5811
The length of the segment AB: |AB| = 3.1623
Vector: AB = (1; -3)
Normal vector: n = (3; 1)
Midpoint of the segment AB: M = [0.5; 3.5]
Perpendicular Bisector equation: x-3y+10 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (1; 2) ; |OB| = 2.2361
Scalar product OA .OB = 10
Angle ∠ AOB = 26°33'54″ = 0.4636 rad