Line slope calculator 2x+y=5
Straight line given by points A[0; 5] and B[1; 3]
Calculation:
Slope: m = -2Slope-intercept form of line: y = -2x+5
Canonical form of the line equation: 2x+y-5 = 0
Parametric form of the line equation:
x = t
y = -2t+5 ; t ∈ R
Slope angle of line: φ = -63°26'6″ = -1.1071 rad
X intercept: x0 = 2.5
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 2.2361
The length of the segment AB: |AB| = 2.2361
Vector: AB = (1; -2)
Normal vector: n = (2; 1)
Midpoint of the segment AB: M = [0.5; 4]
Perpendicular Bisector equation: x-2y+7.5 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (1; 3) ; |OB| = 3.1623
Scalar product OA .OB = 15
Angle ∠ AOB = 18°26'6″ = 0.3218 rad