Line slope calculator 2x+y=5


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[1; 3]

Calculation:

Slope-intercept form of line: y = -2x+5

Canonical form of the line equation: 2x+y-5 = 0

Parametric form of the line equation:
x = t
y = -2t+5      ; t ∈ R

Slope: m = -2

Slope angle of line: φ = -63°26'6″ = -1.1071 rad

X intercept: x0 = 2.5

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 2.2361

The length of the segment AB: |AB| = 2.2361

Vector: AB = (1; -2)

Normal vector: n = (2; 1)

Midpoint of the segment AB: M = [0.5; 4]

Perpendicular Bisector equation: x-2y+7.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (1; 3) ;   |OB| = 3.1623
Scalar product OA .OB = 15
Angle ∠ AOB = 18°26'6″ = 0.3218 rad