Line slope calculator 3x+10y=50


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[0; 5] and B[10; 2]

Calculation:

Slope: m = -0.3

Slope-intercept form of line: y = -0.3x+5

Canonical form of the line equation: 3x+10y-50 = 0

Parametric form of the line equation:
x = 10t
y = -3t+5      ; t ∈ R

Slope angle of line: φ = -16°41'57″ = -0.2915 rad

X intercept: x0 = 16.6667

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.7891

The length of the segment AB: |AB| = 10.4403

Vector: AB = (10; -3)

Normal vector: n = (3; 10)

Midpoint of the segment AB: M = [5; 3.5]

Perpendicular Bisector equation: 10x-3y-39.5 = 0

Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (10; 2) ;   |OB| = 10.198
Scalar product OA .OB = 10
Angle ∠ AOB = 78°41'24″ = 1.3734 rad