Line slope calculator 3x-10y=-50


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[10; 8]

Calculation:

Slope-intercept form of line: y = 0.3x+5

Canonical form of the line equation: 3x-10y+50 = 0

Parametric form of the line equation:
x = 10t
y = 3t+5      ; t ∈ R

Slope: m = 0.3

Slope angle of line: φ = 16°41'57″ = 0.2915 rad

X intercept: x0 = -16.6667

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.7891

The length of the segment AB: |AB| = 10.4403

Vector: AB = (10; 3)

Normal vector: n = (3; -10)

Midpoint of the segment AB: M = [5; 6.5]

Perpendicular Bisector equation: 10x+3y-69.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (10; 8) ;   |OB| = 12.8062
Scalar product OA .OB = 40
Angle ∠ AOB = 51°20'25″ = 0.8961 rad