Line slope calculator 5x+2y=10


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[2; 0]

Calculation:

Slope-intercept form of line: y = -2.5x+5

Canonical form of the line equation: 5x+2y-10 = 0

Parametric form of the line equation:
x = 2t
y = -5t+5      ; t ∈ R

Slope: m = -2.5

Slope angle of line: φ = -68°11'55″ = -1.1903 rad

X intercept: x0 = 2

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 1.857

The length of the segment AB: |AB| = 5.3852

Vector: AB = (2; -5)

Normal vector: n = (5; 2)

Midpoint of the segment AB: M = [1; 2.5]

Perpendicular Bisector equation: 2x-5y+10.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (2; 0) ;   |OB| = 2
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad