Line slope calculator x+2y=10
Straight line given by points A[0; 5] and B[2; 4]
Calculation:
Slope: m = -0.5Slope-intercept form of line: y = -0.5x+5
Canonical form of the line equation: x+2y-10 = 0
Parametric form of the line equation:
x = 2t
y = -t+5 ; t ∈ R
Slope angle of line: φ = -26°33'54″ = -0.4636 rad
X intercept: x0 = 10
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 4.4721
The length of the segment AB: |AB| = 2.2361
Vector: AB = (2; -1)
Normal vector: n = (1; 2)
Midpoint of the segment AB: M = [1; 4.5]
Perpendicular Bisector equation: 2x-y+2.5 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (2; 4) ; |OB| = 4.4721
Scalar product OA .OB = 20
Angle ∠ AOB = 26°33'54″ = 0.4636 rad