Line slope calculator 5x-3y=-15


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[3; 10]

Calculation:

Slope-intercept form of line: y = 1.6667x+5

Canonical form of the line equation: 5x-3y+15 = 0

Parametric form of the line equation:
x = 3t
y = 5t+5      ; t ∈ R

Slope: m = 1.6667

Slope angle of line: φ = 59°2'10″ = 1.0304 rad

X intercept: x0 = -3

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 2.5725

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; 5)

Normal vector: n = (5; -3)

Midpoint of the segment AB: M = [1.5; 7.5]

Perpendicular Bisector equation: 3x+5y-42 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (3; 10) ;   |OB| = 10.4403
Scalar product OA .OB = 50
Angle ∠ AOB = 16°41'57″ = 0.2915 rad