Line slope calculator 5x-3y=-15
Straight line given by points A[0; 5] and B[3; 10]
Calculation:
Slope: m = 1.6667Slope-intercept form of line: y = 1.6667x+5
Canonical form of the line equation: 5x-3y+15 = 0
Parametric form of the line equation:
x = 3t
y = 5t+5 ; t ∈ R
Slope angle of line: φ = 59°2'10″ = 1.0304 rad
X intercept: x0 = -3
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 2.5725
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; 5)
Normal vector: n = (5; -3)
Midpoint of the segment AB: M = [1.5; 7.5]
Perpendicular Bisector equation: 3x+5y-42 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (3; 10) ; |OB| = 10.4403
Scalar product OA .OB = 50
Angle ∠ AOB = 16°41'57″ = 0.2915 rad