Line slope calculator 2x+3y=15


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[0; 5] and B[3; 3]

Calculation:

Slope: m = -0.6667

Slope-intercept form of line: y = -0.6667x+5

Canonical form of the line equation: 2x+3y-15 = 0

Parametric form of the line equation:
x = 3t
y = -2t+5      ; t ∈ R

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 7.5

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.1603

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [1.5; 4]

Perpendicular Bisector equation: 3x-2y+3.5 = 0

Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (3; 3) ;   |OB| = 4.2426
Scalar product OA .OB = 15
Angle ∠ AOB = 45° = 0.7854 rad