Line slope calculator x+3y=15


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[3; 4]

Calculation:

Slope-intercept form of line: y = -0.3333x+5

Canonical form of the line equation: x+3y-15 = 0

Parametric form of the line equation:
x = 3t
y = -t+5      ; t ∈ R

Slope: m = -0.3333

Slope angle of line: φ = -18°26'6″ = -0.3218 rad

X intercept: x0 = 15

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.7434

The length of the segment AB: |AB| = 3.1623

Vector: AB = (3; -1)

Normal vector: n = (1; 3)

Midpoint of the segment AB: M = [1.5; 4.5]

Perpendicular Bisector equation: 3x-y = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (3; 4) ;   |OB| = 5
Scalar product OA .OB = 20
Angle ∠ AOB = 36°52'12″ = 0.6435 rad