Line slope calculator x+3y=15
Straight line given by points A[0; 5] and B[3; 4]
Calculation:
Slope: m = -0.3333Slope-intercept form of line: y = -0.3333x+5
Canonical form of the line equation: x+3y-15 = 0
Parametric form of the line equation:
x = 3t
y = -t+5 ; t ∈ R
Slope angle of line: φ = -18°26'6″ = -0.3218 rad
X intercept: x0 = 15
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 4.7434
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; -1)
Normal vector: n = (1; 3)
Midpoint of the segment AB: M = [1.5; 4.5]
Perpendicular Bisector equation: 3x-y = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (3; 4) ; |OB| = 5
Scalar product OA .OB = 20
Angle ∠ AOB = 36°52'12″ = 0.6435 rad