Line slope calculator x-3y=-15
Straight line given by points A[0; 5] and B[3; 6]
Calculation:
Slope: m = 0.3333Slope-intercept form of line: y = 0.3333x+5
Canonical form of the line equation: x-3y+15 = 0
Parametric form of the line equation:
x = 3t
y = t+5 ; t ∈ R
Slope angle of line: φ = 18°26'6″ = 0.3218 rad
X intercept: x0 = -15
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 4.7434
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; 1)
Normal vector: n = (1; -3)
Midpoint of the segment AB: M = [1.5; 5.5]
Perpendicular Bisector equation: 3x+y-10 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (3; 6) ; |OB| = 6.7082
Scalar product OA .OB = 30
Angle ∠ AOB = 26°33'54″ = 0.4636 rad