Line slope calculator 5x-4y=-20


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[4; 10]

Calculation:

Slope-intercept form of line: y = 1.25x+5

Canonical form of the line equation: 5x-4y+20 = 0

Parametric form of the line equation:
x = 4t
y = 5t+5      ; t ∈ R

Slope: m = 1.25

Slope angle of line: φ = 51°20'25″ = 0.8961 rad

X intercept: x0 = -4

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 3.1235

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; 5)

Normal vector: n = (5; -4)

Midpoint of the segment AB: M = [2; 7.5]

Perpendicular Bisector equation: 4x+5y-45.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (4; 10) ;   |OB| = 10.7703
Scalar product OA .OB = 50
Angle ∠ AOB = 21°48'5″ = 0.3805 rad