Line slope calculator 3x+4y=20


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[4; 2]

Calculation:

Slope-intercept form of line: y = -0.75x+5

Canonical form of the line equation: 3x+4y-20 = 0

Parametric form of the line equation:
x = 4t
y = -3t+5      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 6.6667

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [2; 3.5]

Perpendicular Bisector equation: 4x-3y+2.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (4; 2) ;   |OB| = 4.4721
Scalar product OA .OB = 10
Angle ∠ AOB = 63°26'6″ = 1.1071 rad