Line slope calculator 4x+5y=25


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[5; 1]

Calculation:

Slope-intercept form of line: y = -0.8x+5

Canonical form of the line equation: 4x+5y-25 = 0

Parametric form of the line equation:
x = 5t
y = -4t+5      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 6.25

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 3.9043

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [2.5; 3]

Perpendicular Bisector equation: 5x-4y-0.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (5; 1) ;   |OB| = 5.099
Scalar product OA .OB = 5
Angle ∠ AOB = 78°41'24″ = 1.3734 rad