Line slope calculator 4x+5y=25
Straight line given by points A[0; 5] and B[5; 1]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+5
Canonical form of the line equation: 4x+5y-25 = 0
Parametric form of the line equation:
x = 5t
y = -4t+5 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 6.25
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 3.9043
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [2.5; 3]
Perpendicular Bisector equation: 5x-4y-0.5 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 5
Angle ∠ AOB = 78°41'24″ = 1.3734 rad