Line slope calculator 3x+5y=25


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[5; 2]

Calculation:

Slope-intercept form of line: y = -0.6x+5

Canonical form of the line equation: 3x+5y-25 = 0

Parametric form of the line equation:
x = 5t
y = -3t+5      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 8.3333

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.2875

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [2.5; 3.5]

Perpendicular Bisector equation: 5x-3y-2 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (5; 2) ;   |OB| = 5.3852
Scalar product OA .OB = 10
Angle ∠ AOB = 68°11'55″ = 1.1903 rad