Line slope calculator 2x+5y=25


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[5; 3]

Calculation:

Slope-intercept form of line: y = -0.4x+5

Canonical form of the line equation: 2x+5y-25 = 0

Parametric form of the line equation:
x = 5t
y = -2t+5      ; t ∈ R

Slope: m = -0.4

Slope angle of line: φ = -21°48'5″ = -0.3805 rad

X intercept: x0 = 12.5

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.6424

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; -2)

Normal vector: n = (2; 5)

Midpoint of the segment AB: M = [2.5; 4]

Perpendicular Bisector equation: 5x-2y-4.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (5; 3) ;   |OB| = 5.831
Scalar product OA .OB = 15
Angle ∠ AOB = 59°2'10″ = 1.0304 rad