Line slope calculator x-5y=-25


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[5; 6]

Calculation:

Slope-intercept form of line: y = 0.2x+5

Canonical form of the line equation: x-5y+25 = 0

Parametric form of the line equation:
x = 5t
y = t+5      ; t ∈ R

Slope: m = 0.2

Slope angle of line: φ = 11°18'36″ = 0.1974 rad

X intercept: x0 = -25

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.9029

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; 1)

Normal vector: n = (1; -5)

Midpoint of the segment AB: M = [2.5; 5.5]

Perpendicular Bisector equation: 5x+y-18 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (5; 6) ;   |OB| = 7.8102
Scalar product OA .OB = 30
Angle ∠ AOB = 39°48'20″ = 0.6947 rad