Line slope calculator 3x-5y=-25
Straight line given by points A[0; 5] and B[5; 8]
Calculation:
Slope: m = 0.6Slope-intercept form of line: y = 0.6x+5
Canonical form of the line equation: 3x-5y+25 = 0
Parametric form of the line equation:
x = 5t
y = 3t+5 ; t ∈ R
Slope angle of line: φ = 30°57'50″ = 0.5404 rad
X intercept: x0 = -8.3333
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 4.2875
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; 3)
Normal vector: n = (3; -5)
Midpoint of the segment AB: M = [2.5; 6.5]
Perpendicular Bisector equation: 5x+3y-32 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (5; 8) ; |OB| = 9.434
Scalar product OA .OB = 40
Angle ∠ AOB = 32°19″ = 0.5586 rad