Line slope calculator 5x+6y=30


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[6; 0]

Calculation:

Slope-intercept form of line: y = -0.8333x+5

Canonical form of the line equation: 5x+6y-30 = 0

Parametric form of the line equation:
x = 6t
y = -5t+5      ; t ∈ R

Slope: m = -0.8333

Slope angle of line: φ = -39°48'20″ = -0.6947 rad

X intercept: x0 = 6

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 3.8411

The length of the segment AB: |AB| = 7.8102

Vector: AB = (6; -5)

Normal vector: n = (5; 6)

Midpoint of the segment AB: M = [3; 2.5]

Perpendicular Bisector equation: 6x-5y-5.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (6; 0) ;   |OB| = 6
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad