Line slope calculator 5x+7y=35
Straight line given by points A[0; 5] and B[7; 0]
Calculation:
Slope: m = -0.7143Slope-intercept form of line: y = -0.7143x+5
Canonical form of the line equation: 5x+7y-35 = 0
Parametric form of the line equation:
x = 7t
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -35°32'16″ = -0.6202 rad
X intercept: x0 = 7
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 4.0687
The length of the segment AB: |AB| = 8.6023
Vector: AB = (7; -5)
Normal vector: n = (5; 7)
Midpoint of the segment AB: M = [3.5; 2.5]
Perpendicular Bisector equation: 7x-5y-12 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (7; 0) ; |OB| = 7
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad