Line slope calculator 3x+7y=35


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[7; 2]

Calculation:

Slope-intercept form of line: y = -0.4286x+5

Canonical form of the line equation: 3x+7y-35 = 0

Parametric form of the line equation:
x = 7t
y = -3t+5      ; t ∈ R

Slope: m = -0.4286

Slope angle of line: φ = -23°11'55″ = -0.4049 rad

X intercept: x0 = 11.6667

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.5957

The length of the segment AB: |AB| = 7.6158

Vector: AB = (7; -3)

Normal vector: n = (3; 7)

Midpoint of the segment AB: M = [3.5; 3.5]

Perpendicular Bisector equation: 7x-3y-14 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (7; 2) ;   |OB| = 7.2801
Scalar product OA .OB = 10
Angle ∠ AOB = 74°3'17″ = 1.2925 rad