Line slope calculator 5x+8y=40
Straight line given by points A[0; 5] and B[8; 0]
Calculation:
Slope: m = -0.625Slope-intercept form of line: y = -0.625x+5
Canonical form of the line equation: 5x+8y-40 = 0
Parametric form of the line equation:
x = 8t
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -32°19″ = -0.5586 rad
X intercept: x0 = 8
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 4.24
The length of the segment AB: |AB| = 9.434
Vector: AB = (8; -5)
Normal vector: n = (5; 8)
Midpoint of the segment AB: M = [4; 2.5]
Perpendicular Bisector equation: 8x-5y-19.5 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (8; 0) ; |OB| = 8
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad