Line slope calculator 5x+8y=40


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[8; 0]

Calculation:

Slope-intercept form of line: y = -0.625x+5

Canonical form of the line equation: 5x+8y-40 = 0

Parametric form of the line equation:
x = 8t
y = -5t+5      ; t ∈ R

Slope: m = -0.625

Slope angle of line: φ = -32°19″ = -0.5586 rad

X intercept: x0 = 8

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.24

The length of the segment AB: |AB| = 9.434

Vector: AB = (8; -5)

Normal vector: n = (5; 8)

Midpoint of the segment AB: M = [4; 2.5]

Perpendicular Bisector equation: 8x-5y-19.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (8; 0) ;   |OB| = 8
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad