Line slope calculator 5x-8y=-40


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[8; 10]

Calculation:

Slope-intercept form of line: y = 0.625x+5

Canonical form of the line equation: 5x-8y+40 = 0

Parametric form of the line equation:
x = 8t
y = 5t+5      ; t ∈ R

Slope: m = 0.625

Slope angle of line: φ = 32°19″ = 0.5586 rad

X intercept: x0 = -8

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.24

The length of the segment AB: |AB| = 9.434

Vector: AB = (8; 5)

Normal vector: n = (5; -8)

Midpoint of the segment AB: M = [4; 7.5]

Perpendicular Bisector equation: 8x+5y-69.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (8; 10) ;   |OB| = 12.8062
Scalar product OA .OB = 50
Angle ∠ AOB = 38°39'35″ = 0.6747 rad