Line slope calculator 5x-8y=-40
Straight line given by points A[0; 5] and B[8; 10]
Calculation:
Slope: m = 0.625Slope-intercept form of line: y = 0.625x+5
Canonical form of the line equation: 5x-8y+40 = 0
Parametric form of the line equation:
x = 8t
y = 5t+5 ; t ∈ R
Slope angle of line: φ = 32°19″ = 0.5586 rad
X intercept: x0 = -8
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 4.24
The length of the segment AB: |AB| = 9.434
Vector: AB = (8; 5)
Normal vector: n = (5; -8)
Midpoint of the segment AB: M = [4; 7.5]
Perpendicular Bisector equation: 8x+5y-69.5 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (8; 10) ; |OB| = 12.8062
Scalar product OA .OB = 50
Angle ∠ AOB = 38°39'35″ = 0.6747 rad