Line slope calculator 3x+8y=40


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[8; 2]

Calculation:

Slope-intercept form of line: y = -0.375x+5

Canonical form of the line equation: 3x+8y-40 = 0

Parametric form of the line equation:
x = 8t
y = -3t+5      ; t ∈ R

Slope: m = -0.375

Slope angle of line: φ = -20°33'22″ = -0.3588 rad

X intercept: x0 = 13.3333

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.6816

The length of the segment AB: |AB| = 8.544

Vector: AB = (8; -3)

Normal vector: n = (3; 8)

Midpoint of the segment AB: M = [4; 3.5]

Perpendicular Bisector equation: 8x-3y-21.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (8; 2) ;   |OB| = 8.2462
Scalar product OA .OB = 10
Angle ∠ AOB = 75°57'50″ = 1.3258 rad