Line slope calculator 3x+8y=40
Straight line given by points A[0; 5] and B[8; 2]
Calculation:
Slope: m = -0.375Slope-intercept form of line: y = -0.375x+5
Canonical form of the line equation: 3x+8y-40 = 0
Parametric form of the line equation:
x = 8t
y = -3t+5 ; t ∈ R
Slope angle of line: φ = -20°33'22″ = -0.3588 rad
X intercept: x0 = 13.3333
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 4.6816
The length of the segment AB: |AB| = 8.544
Vector: AB = (8; -3)
Normal vector: n = (3; 8)
Midpoint of the segment AB: M = [4; 3.5]
Perpendicular Bisector equation: 8x-3y-21.5 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (8; 2) ; |OB| = 8.2462
Scalar product OA .OB = 10
Angle ∠ AOB = 75°57'50″ = 1.3258 rad