Line slope calculator x-8y=-40


Enter coordinates of two different points:

Straight line given by points A[0; 5] and B[8; 6]

Calculation:

Slope-intercept form of line: y = 0.125x+5

Canonical form of the line equation: x-8y+40 = 0

Parametric form of the line equation:
x = 8t
y = t+5      ; t ∈ R

Slope: m = 0.125

Slope angle of line: φ = 7°7'30″ = 0.1244 rad

X intercept: x0 = -40

Y intercept: y0 = q = 5

Distance line from the origin: d0 = 4.9614

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; 1)

Normal vector: n = (1; -8)

Midpoint of the segment AB: M = [4; 5.5]

Perpendicular Bisector equation: 8x+y-37.5 = 0


Vector OA = (0; 5) ;   |OA| = 5
Vector OB = (8; 6) ;   |OB| = 10
Scalar product OA .OB = 30
Angle ∠ AOB = 53°7'48″ = 0.9273 rad