Line slope calculator 4x+9y=45
Straight line given by points A[0; 5] and B[9; 1]
Calculation:
Slope: m = -0.4444Slope-intercept form of line: y = -0.4444x+5
Canonical form of the line equation: 4x+9y-45 = 0
Parametric form of the line equation:
x = 9t
y = -4t+5 ; t ∈ R
Slope angle of line: φ = -23°57'45″ = -0.4182 rad
X intercept: x0 = 11.25
Y intercept: y0 = q = 5
Distance line from the origin: d0 = 4.5691
The length of the segment AB: |AB| = 9.8489
Vector: AB = (9; -4)
Normal vector: n = (4; 9)
Midpoint of the segment AB: M = [4.5; 3]
Perpendicular Bisector equation: 9x-4y-28.5 = 0
Vector OA = (0; 5) ; |OA| = 5
Vector OB = (9; 1) ; |OB| = 9.0554
Scalar product OA .OB = 5
Angle ∠ AOB = 83°39'35″ = 1.4601 rad