Line slope calculator 4x+y=6


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[1; 2]

Calculation:

Slope-intercept form of line: y = -4x+6

Canonical form of the line equation: 4x+y-6 = 0

Parametric form of the line equation:
x = t
y = -4t+6      ; t ∈ R

Slope: m = -4

Slope angle of line: φ = -75°57'50″ = -1.3258 rad

X intercept: x0 = 1.5

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 1.4552

The length of the segment AB: |AB| = 4.1231

Vector: AB = (1; -4)

Normal vector: n = (4; 1)

Midpoint of the segment AB: M = [0.5; 4]

Perpendicular Bisector equation: x-4y+15.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (1; 2) ;   |OB| = 2.2361
Scalar product OA .OB = 12
Angle ∠ AOB = 26°33'54″ = 0.4636 rad