Line slope calculator 3x+10y=60
Straight line given by points A[0; 6] and B[10; 3]
Calculation:
Slope: m = -0.3Slope-intercept form of line: y = -0.3x+6
Canonical form of the line equation: 3x+10y-60 = 0
Parametric form of the line equation:
x = 10t
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -16°41'57″ = -0.2915 rad
X intercept: x0 = 20
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 5.747
The length of the segment AB: |AB| = 10.4403
Vector: AB = (10; -3)
Normal vector: n = (3; 10)
Midpoint of the segment AB: M = [5; 4.5]
Perpendicular Bisector equation: 10x-3y-36.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 18
Angle ∠ AOB = 73°18'3″ = 1.2793 rad