Line slope calculator 3x+10y=60


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[10; 3]

Calculation:

Slope-intercept form of line: y = -0.3x+6

Canonical form of the line equation: 3x+10y-60 = 0

Parametric form of the line equation:
x = 10t
y = -3t+6      ; t ∈ R

Slope: m = -0.3

Slope angle of line: φ = -16°41'57″ = -0.2915 rad

X intercept: x0 = 20

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 5.747

The length of the segment AB: |AB| = 10.4403

Vector: AB = (10; -3)

Normal vector: n = (3; 10)

Midpoint of the segment AB: M = [5; 4.5]

Perpendicular Bisector equation: 10x-3y-36.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 18
Angle ∠ AOB = 73°18'3″ = 1.2793 rad