Line slope calculator x+10y=60


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[10; 5]

Calculation:

Slope-intercept form of line: y = -0.1x+6

Canonical form of the line equation: x+10y-60 = 0

Parametric form of the line equation:
x = 10t
y = -t+6      ; t ∈ R

Slope: m = -0.1

Slope angle of line: φ = -5°42'38″ = -0.0997 rad

X intercept: x0 = 60

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 5.9702

The length of the segment AB: |AB| = 10.0499

Vector: AB = (10; -1)

Normal vector: n = (1; 10)

Midpoint of the segment AB: M = [5; 5.5]

Perpendicular Bisector equation: 10x-y-44.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (10; 5) ;   |OB| = 11.1803
Scalar product OA .OB = 30
Angle ∠ AOB = 63°26'6″ = 1.1071 rad