Line slope calculator x+10y=60
Straight line given by points A[0; 6] and B[10; 5]
Calculation:
Slope: m = -0.1Slope-intercept form of line: y = -0.1x+6
Canonical form of the line equation: x+10y-60 = 0
Parametric form of the line equation:
x = 10t
y = -t+6 ; t ∈ R
Slope angle of line: φ = -5°42'38″ = -0.0997 rad
X intercept: x0 = 60
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 5.9702
The length of the segment AB: |AB| = 10.0499
Vector: AB = (10; -1)
Normal vector: n = (1; 10)
Midpoint of the segment AB: M = [5; 5.5]
Perpendicular Bisector equation: 10x-y-44.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 30
Angle ∠ AOB = 63°26'6″ = 1.1071 rad