Line slope calculator 5x+2y=12
Straight line given by points A[0; 6] and B[2; 1]
Calculation:
Slope: m = -2.5Slope-intercept form of line: y = -2.5x+6
Canonical form of the line equation: 5x+2y-12 = 0
Parametric form of the line equation:
x = 2t
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -68°11'55″ = -1.1903 rad
X intercept: x0 = 2.4
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 2.2283
The length of the segment AB: |AB| = 5.3852
Vector: AB = (2; -5)
Normal vector: n = (5; 2)
Midpoint of the segment AB: M = [1; 3.5]
Perpendicular Bisector equation: 2x-5y+15.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (2; 1) ; |OB| = 2.2361
Scalar product OA .OB = 6
Angle ∠ AOB = 63°26'6″ = 1.1071 rad