Line slope calculator 5x+2y=12


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[2; 1]

Calculation:

Slope-intercept form of line: y = -2.5x+6

Canonical form of the line equation: 5x+2y-12 = 0

Parametric form of the line equation:
x = 2t
y = -5t+6      ; t ∈ R

Slope: m = -2.5

Slope angle of line: φ = -68°11'55″ = -1.1903 rad

X intercept: x0 = 2.4

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 2.2283

The length of the segment AB: |AB| = 5.3852

Vector: AB = (2; -5)

Normal vector: n = (5; 2)

Midpoint of the segment AB: M = [1; 3.5]

Perpendicular Bisector equation: 2x-5y+15.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (2; 1) ;   |OB| = 2.2361
Scalar product OA .OB = 6
Angle ∠ AOB = 63°26'6″ = 1.1071 rad