Line slope calculator 3x+2y=12


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[2; 3]

Calculation:

Slope-intercept form of line: y = -1.5x+6

Canonical form of the line equation: 3x+2y-12 = 0

Parametric form of the line equation:
x = 2t
y = -3t+6      ; t ∈ R

Slope: m = -1.5

Slope angle of line: φ = -56°18'36″ = -0.9828 rad

X intercept: x0 = 4

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 3.3282

The length of the segment AB: |AB| = 3.6056

Vector: AB = (2; -3)

Normal vector: n = (3; 2)

Midpoint of the segment AB: M = [1; 4.5]

Perpendicular Bisector equation: 2x-3y+11.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (2; 3) ;   |OB| = 3.6056
Scalar product OA .OB = 18
Angle ∠ AOB = 33°41'24″ = 0.588 rad