Line slope calculator 4x-3y=-18
Straight line given by points A[0; 6] and B[3; 10]
Calculation:
Slope: m = 1.3333Slope-intercept form of line: y = 1.3333x+6
Canonical form of the line equation: 4x-3y+18 = 0
Parametric form of the line equation:
x = 3t
y = 4t+6 ; t ∈ R
Slope angle of line: φ = 53°7'48″ = 0.9273 rad
X intercept: x0 = -4.5
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 3.6
The length of the segment AB: |AB| = 5
Vector: AB = (3; 4)
Normal vector: n = (4; -3)
Midpoint of the segment AB: M = [1.5; 8]
Perpendicular Bisector equation: 3x+4y-36.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (3; 10) ; |OB| = 10.4403
Scalar product OA .OB = 60
Angle ∠ AOB = 16°41'57″ = 0.2915 rad