Line slope calculator 4x+3y=18
Straight line given by points A[0; 6] and B[3; 2]
Calculation:
Slope: m = -1.3333Slope-intercept form of line: y = -1.3333x+6
Canonical form of the line equation: 4x+3y-18 = 0
Parametric form of the line equation:
x = 3t
y = -4t+6 ; t ∈ R
Slope angle of line: φ = -53°7'48″ = -0.9273 rad
X intercept: x0 = 4.5
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 3.6
The length of the segment AB: |AB| = 5
Vector: AB = (3; -4)
Normal vector: n = (4; 3)
Midpoint of the segment AB: M = [1.5; 4]
Perpendicular Bisector equation: 3x-4y+11.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (3; 2) ; |OB| = 3.6056
Scalar product OA .OB = 12
Angle ∠ AOB = 56°18'36″ = 0.9828 rad