Line slope calculator 2x+3y=18


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[3; 4]

Calculation:

Slope-intercept form of line: y = -0.6667x+6

Canonical form of the line equation: 2x+3y-18 = 0

Parametric form of the line equation:
x = 3t
y = -2t+6      ; t ∈ R

Slope: m = -0.6667

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 9

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 4.9923

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [1.5; 5]

Perpendicular Bisector equation: 3x-2y+5.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (3; 4) ;   |OB| = 5
Scalar product OA .OB = 24
Angle ∠ AOB = 36°52'12″ = 0.6435 rad