Line slope calculator 5x+4y=24


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[4; 1]

Calculation:

Slope-intercept form of line: y = -1.25x+6

Canonical form of the line equation: 5x+4y-24 = 0

Parametric form of the line equation:
x = 4t
y = -5t+6      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 4.8

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 3.7482

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [2; 3.5]

Perpendicular Bisector equation: 4x-5y+9.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (4; 1) ;   |OB| = 4.1231
Scalar product OA .OB = 6
Angle ∠ AOB = 75°57'50″ = 1.3258 rad