Line slope calculator 5x+4y=24
Straight line given by points A[0; 6] and B[4; 1]
Calculation:
Slope: m = -1.25Slope-intercept form of line: y = -1.25x+6
Canonical form of the line equation: 5x+4y-24 = 0
Parametric form of the line equation:
x = 4t
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -51°20'25″ = -0.8961 rad
X intercept: x0 = 4.8
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 3.7482
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; -5)
Normal vector: n = (5; 4)
Midpoint of the segment AB: M = [2; 3.5]
Perpendicular Bisector equation: 4x-5y+9.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (4; 1) ; |OB| = 4.1231
Scalar product OA .OB = 6
Angle ∠ AOB = 75°57'50″ = 1.3258 rad