Line slope calculator 3x+4y=24
Straight line given by points A[0; 6] and B[4; 3]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+6
Canonical form of the line equation: 3x+4y-24 = 0
Parametric form of the line equation:
x = 4t
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 8
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 4.8
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [2; 4.5]
Perpendicular Bisector equation: 4x-3y+5.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (4; 3) ; |OB| = 5
Scalar product OA .OB = 18
Angle ∠ AOB = 53°7'48″ = 0.9273 rad