Line slope calculator 5x+6y=36


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[6; 1]

Calculation:

Slope-intercept form of line: y = -0.8333x+6

Canonical form of the line equation: 5x+6y-36 = 0

Parametric form of the line equation:
x = 6t
y = -5t+6      ; t ∈ R

Slope: m = -0.8333

Slope angle of line: φ = -39°48'20″ = -0.6947 rad

X intercept: x0 = 7.2

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 4.6093

The length of the segment AB: |AB| = 7.8102

Vector: AB = (6; -5)

Normal vector: n = (5; 6)

Midpoint of the segment AB: M = [3; 3.5]

Perpendicular Bisector equation: 6x-5y-0.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (6; 1) ;   |OB| = 6.0828
Scalar product OA .OB = 6
Angle ∠ AOB = 80°32'16″ = 1.4056 rad