Line slope calculator 5x+6y=36
Straight line given by points A[0; 6] and B[6; 1]
Calculation:
Slope: m = -0.8333Slope-intercept form of line: y = -0.8333x+6
Canonical form of the line equation: 5x+6y-36 = 0
Parametric form of the line equation:
x = 6t
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -39°48'20″ = -0.6947 rad
X intercept: x0 = 7.2
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 4.6093
The length of the segment AB: |AB| = 7.8102
Vector: AB = (6; -5)
Normal vector: n = (5; 6)
Midpoint of the segment AB: M = [3; 3.5]
Perpendicular Bisector equation: 6x-5y-0.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (6; 1) ; |OB| = 6.0828
Scalar product OA .OB = 6
Angle ∠ AOB = 80°32'16″ = 1.4056 rad