Line slope calculator 5x+8y=48


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -0.625x+6

Canonical form of the line equation: 5x+8y-48 = 0

Parametric form of the line equation:
x = 8t
y = -5t+6      ; t ∈ R

Slope: m = -0.625

Slope angle of line: φ = -32°19″ = -0.5586 rad

X intercept: x0 = 9.6

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 5.088

The length of the segment AB: |AB| = 9.434

Vector: AB = (8; -5)

Normal vector: n = (5; 8)

Midpoint of the segment AB: M = [4; 3.5]

Perpendicular Bisector equation: 8x-5y-14.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 6
Angle ∠ AOB = 82°52'30″ = 1.4464 rad