Line slope calculator 3x+8y=48


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[8; 3]

Calculation:

Slope-intercept form of line: y = -0.375x+6

Canonical form of the line equation: 3x+8y-48 = 0

Parametric form of the line equation:
x = 8t
y = -3t+6      ; t ∈ R

Slope: m = -0.375

Slope angle of line: φ = -20°33'22″ = -0.3588 rad

X intercept: x0 = 16

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 5.618

The length of the segment AB: |AB| = 8.544

Vector: AB = (8; -3)

Normal vector: n = (3; 8)

Midpoint of the segment AB: M = [4; 4.5]

Perpendicular Bisector equation: 8x-3y-18.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (8; 3) ;   |OB| = 8.544
Scalar product OA .OB = 18
Angle ∠ AOB = 69°26'38″ = 1.212 rad