Line slope calculator x+8y=48


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[8; 5]

Calculation:

Slope-intercept form of line: y = -0.125x+6

Canonical form of the line equation: x+8y-48 = 0

Parametric form of the line equation:
x = 8t
y = -t+6      ; t ∈ R

Slope: m = -0.125

Slope angle of line: φ = -7°7'30″ = -0.1244 rad

X intercept: x0 = 48

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 5.9537

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; -1)

Normal vector: n = (1; 8)

Midpoint of the segment AB: M = [4; 5.5]

Perpendicular Bisector equation: 8x-y-26.5 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (8; 5) ;   |OB| = 9.434
Scalar product OA .OB = 30
Angle ∠ AOB = 57°59'41″ = 1.0122 rad