Line slope calculator x+8y=48
Straight line given by points A[0; 6] and B[8; 5]
Calculation:
Slope: m = -0.125Slope-intercept form of line: y = -0.125x+6
Canonical form of the line equation: x+8y-48 = 0
Parametric form of the line equation:
x = 8t
y = -t+6 ; t ∈ R
Slope angle of line: φ = -7°7'30″ = -0.1244 rad
X intercept: x0 = 48
Y intercept: y0 = q = 6
Distance line from the origin: d0 = 5.9537
The length of the segment AB: |AB| = 8.0623
Vector: AB = (8; -1)
Normal vector: n = (1; 8)
Midpoint of the segment AB: M = [4; 5.5]
Perpendicular Bisector equation: 8x-y-26.5 = 0
Vector OA = (0; 6) ; |OA| = 6
Vector OB = (8; 5) ; |OB| = 9.434
Scalar product OA .OB = 30
Angle ∠ AOB = 57°59'41″ = 1.0122 rad