Line slope calculator 2x-8y=-48


Enter coordinates of two different points:

Straight line given by points A[0; 6] and B[8; 8]

Calculation:

Slope-intercept form of line: y = 0.25x+6

Canonical form of the line equation: 2x-8y+48 = 0

Parametric form of the line equation:
x = 8t
y = 2t+6      ; t ∈ R

Slope: m = 0.25

Slope angle of line: φ = 14°2'10″ = 0.245 rad

X intercept: x0 = -24

Y intercept: y0 = q = 6

Distance line from the origin: d0 = 5.8209

The length of the segment AB: |AB| = 8.2462

Vector: AB = (8; 2)

Normal vector: n = (2; -8)

Midpoint of the segment AB: M = [4; 7]

Perpendicular Bisector equation: 8x+2y-46 = 0


Vector OA = (0; 6) ;   |OA| = 6
Vector OB = (8; 8) ;   |OB| = 11.3137
Scalar product OA .OB = 48
Angle ∠ AOB = 45° = 0.7854 rad