Line slope calculator 3x+y=8
Straight line given by points A[0; 8] and B[1; 5]
Calculation:
Slope: m = -3Slope-intercept form of line: y = -3x+8
Canonical form of the line equation: 3x+y-8 = 0
Parametric form of the line equation:
x = t
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -71°33'54″ = -1.249 rad
X intercept: x0 = 2.6667
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 2.5298
The length of the segment AB: |AB| = 3.1623
Vector: AB = (1; -3)
Normal vector: n = (3; 1)
Midpoint of the segment AB: M = [0.5; 6.5]
Perpendicular Bisector equation: x-3y+19 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (1; 5) ; |OB| = 5.099
Scalar product OA .OB = 40
Angle ∠ AOB = 11°18'36″ = 0.1974 rad