Line slope calculator 7x+10y=80


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[10; 1]

Calculation:

Slope-intercept form of line: y = -0.7x+8

Canonical form of the line equation: 7x+10y-80 = 0

Parametric form of the line equation:
x = 10t
y = -7t+8      ; t ∈ R

Slope: m = -0.7

Slope angle of line: φ = -34°59'31″ = -0.6107 rad

X intercept: x0 = 11.4286

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 6.5539

The length of the segment AB: |AB| = 12.2066

Vector: AB = (10; -7)

Normal vector: n = (7; 10)

Midpoint of the segment AB: M = [5; 4.5]

Perpendicular Bisector equation: 10x-7y-18.5 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (10; 1) ;   |OB| = 10.0499
Scalar product OA .OB = 8
Angle ∠ AOB = 84°17'22″ = 1.4711 rad