Line slope calculator 7x+10y=80
Straight line given by points A[0; 8] and B[10; 1]
Calculation:
Slope: m = -0.7Slope-intercept form of line: y = -0.7x+8
Canonical form of the line equation: 7x+10y-80 = 0
Parametric form of the line equation:
x = 10t
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -34°59'31″ = -0.6107 rad
X intercept: x0 = 11.4286
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 6.5539
The length of the segment AB: |AB| = 12.2066
Vector: AB = (10; -7)
Normal vector: n = (7; 10)
Midpoint of the segment AB: M = [5; 4.5]
Perpendicular Bisector equation: 10x-7y-18.5 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (10; 1) ; |OB| = 10.0499
Scalar product OA .OB = 8
Angle ∠ AOB = 84°17'22″ = 1.4711 rad