Line slope calculator 2x+10y=80


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[10; 6]

Calculation:

Slope-intercept form of line: y = -0.2x+8

Canonical form of the line equation: 2x+10y-80 = 0

Parametric form of the line equation:
x = 10t
y = -2t+8      ; t ∈ R

Slope: m = -0.2

Slope angle of line: φ = -11°18'36″ = -0.1974 rad

X intercept: x0 = 40

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 7.8446

The length of the segment AB: |AB| = 10.198

Vector: AB = (10; -2)

Normal vector: n = (2; 10)

Midpoint of the segment AB: M = [5; 7]

Perpendicular Bisector equation: 10x-2y-36 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (10; 6) ;   |OB| = 11.6619
Scalar product OA .OB = 48
Angle ∠ AOB = 59°2'10″ = 1.0304 rad