Line slope calculator 2x+10y=80
Straight line given by points A[0; 8] and B[10; 6]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+8
Canonical form of the line equation: 2x+10y-80 = 0
Parametric form of the line equation:
x = 10t
y = -2t+8 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 40
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 7.8446
The length of the segment AB: |AB| = 10.198
Vector: AB = (10; -2)
Normal vector: n = (2; 10)
Midpoint of the segment AB: M = [5; 7]
Perpendicular Bisector equation: 10x-2y-36 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (10; 6) ; |OB| = 11.6619
Scalar product OA .OB = 48
Angle ∠ AOB = 59°2'10″ = 1.0304 rad