Line slope calculator 7x+2y=16
Straight line given by points A[0; 8] and B[2; 1]
Calculation:
Slope: m = -3.5Slope-intercept form of line: y = -3.5x+8
Canonical form of the line equation: 7x+2y-16 = 0
Parametric form of the line equation:
x = 2t
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -74°3'17″ = -1.2925 rad
X intercept: x0 = 2.2857
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 2.1978
The length of the segment AB: |AB| = 7.2801
Vector: AB = (2; -7)
Normal vector: n = (7; 2)
Midpoint of the segment AB: M = [1; 4.5]
Perpendicular Bisector equation: 2x-7y+29.5 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (2; 1) ; |OB| = 2.2361
Scalar product OA .OB = 8
Angle ∠ AOB = 63°26'6″ = 1.1071 rad