Line slope calculator 7x+2y=16


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[2; 1]

Calculation:

Slope-intercept form of line: y = -3.5x+8

Canonical form of the line equation: 7x+2y-16 = 0

Parametric form of the line equation:
x = 2t
y = -7t+8      ; t ∈ R

Slope: m = -3.5

Slope angle of line: φ = -74°3'17″ = -1.2925 rad

X intercept: x0 = 2.2857

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 2.1978

The length of the segment AB: |AB| = 7.2801

Vector: AB = (2; -7)

Normal vector: n = (7; 2)

Midpoint of the segment AB: M = [1; 4.5]

Perpendicular Bisector equation: 2x-7y+29.5 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (2; 1) ;   |OB| = 2.2361
Scalar product OA .OB = 8
Angle ∠ AOB = 63°26'6″ = 1.1071 rad