Line slope calculator 5x+2y=16


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[2; 3]

Calculation:

Slope-intercept form of line: y = -2.5x+8

Canonical form of the line equation: 5x+2y-16 = 0

Parametric form of the line equation:
x = 2t
y = -5t+8      ; t ∈ R

Slope: m = -2.5

Slope angle of line: φ = -68°11'55″ = -1.1903 rad

X intercept: x0 = 3.2

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 2.9711

The length of the segment AB: |AB| = 5.3852

Vector: AB = (2; -5)

Normal vector: n = (5; 2)

Midpoint of the segment AB: M = [1; 5.5]

Perpendicular Bisector equation: 2x-5y+25.5 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (2; 3) ;   |OB| = 3.6056
Scalar product OA .OB = 24
Angle ∠ AOB = 33°41'24″ = 0.588 rad