Line slope calculator 3x+2y=16
Straight line given by points A[0; 8] and B[2; 5]
Calculation:
Slope: m = -1.5Slope-intercept form of line: y = -1.5x+8
Canonical form of the line equation: 3x+2y-16 = 0
Parametric form of the line equation:
x = 2t
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -56°18'36″ = -0.9828 rad
X intercept: x0 = 5.3333
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 4.4376
The length of the segment AB: |AB| = 3.6056
Vector: AB = (2; -3)
Normal vector: n = (3; 2)
Midpoint of the segment AB: M = [1; 6.5]
Perpendicular Bisector equation: 2x-3y+17.5 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (2; 5) ; |OB| = 5.3852
Scalar product OA .OB = 40
Angle ∠ AOB = 21°48'5″ = 0.3805 rad