Line slope calculator 7x+4y=32


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[4; 1]

Calculation:

Slope-intercept form of line: y = -1.75x+8

Canonical form of the line equation: 7x+4y-32 = 0

Parametric form of the line equation:
x = 4t
y = -7t+8      ; t ∈ R

Slope: m = -1.75

Slope angle of line: φ = -60°15'18″ = -1.0517 rad

X intercept: x0 = 4.5714

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 3.9691

The length of the segment AB: |AB| = 8.0623

Vector: AB = (4; -7)

Normal vector: n = (7; 4)

Midpoint of the segment AB: M = [2; 4.5]

Perpendicular Bisector equation: 4x-7y+23.5 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (4; 1) ;   |OB| = 4.1231
Scalar product OA .OB = 8
Angle ∠ AOB = 75°57'50″ = 1.3258 rad