Line slope calculator 7x+4y=32
Straight line given by points A[0; 8] and B[4; 1]
Calculation:
Slope: m = -1.75Slope-intercept form of line: y = -1.75x+8
Canonical form of the line equation: 7x+4y-32 = 0
Parametric form of the line equation:
x = 4t
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -60°15'18″ = -1.0517 rad
X intercept: x0 = 4.5714
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 3.9691
The length of the segment AB: |AB| = 8.0623
Vector: AB = (4; -7)
Normal vector: n = (7; 4)
Midpoint of the segment AB: M = [2; 4.5]
Perpendicular Bisector equation: 4x-7y+23.5 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (4; 1) ; |OB| = 4.1231
Scalar product OA .OB = 8
Angle ∠ AOB = 75°57'50″ = 1.3258 rad