Line slope calculator 2x-4y=-32


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[4; 10]

Calculation:

Slope-intercept form of line: y = 0.5x+8

Canonical form of the line equation: 2x-4y+32 = 0

Parametric form of the line equation:
x = 4t
y = 2t+8      ; t ∈ R

Slope: m = 0.5

Slope angle of line: φ = 26°33'54″ = 0.4636 rad

X intercept: x0 = -16

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 7.1554

The length of the segment AB: |AB| = 4.4721

Vector: AB = (4; 2)

Normal vector: n = (2; -4)

Midpoint of the segment AB: M = [2; 9]

Perpendicular Bisector equation: 4x+2y-26 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (4; 10) ;   |OB| = 10.7703
Scalar product OA .OB = 80
Angle ∠ AOB = 21°48'5″ = 0.3805 rad