Line slope calculator 5x+4y=32


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[4; 3]

Calculation:

Slope-intercept form of line: y = -1.25x+8

Canonical form of the line equation: 5x+4y-32 = 0

Parametric form of the line equation:
x = 4t
y = -5t+8      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 6.4

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 4.9976

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [2; 5.5]

Perpendicular Bisector equation: 4x-5y+19.5 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (4; 3) ;   |OB| = 5
Scalar product OA .OB = 24
Angle ∠ AOB = 53°7'48″ = 0.9273 rad